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-32x^2-288x+1152=0
a = -32; b = -288; c = +1152;
Δ = b2-4ac
Δ = -2882-4·(-32)·1152
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{230400}=480$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-288)-480}{2*-32}=\frac{-192}{-64} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-288)+480}{2*-32}=\frac{768}{-64} =-12 $
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